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x^2-1.6x-1.28=0
a = 1; b = -1.6; c = -1.28;
Δ = b2-4ac
Δ = -1.62-4·1·(-1.28)
Δ = 7.68
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.6)-\sqrt{7.68}}{2*1}=\frac{1.6-\sqrt{7.68}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.6)+\sqrt{7.68}}{2*1}=\frac{1.6+\sqrt{7.68}}{2} $
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